Question

sum of two numbers is 28 and difference between their squares is 112.
a)(x+y) (x-y)=
b)what is the difference between the numbers?
c) Find the numbers? ​

Answer 1

Answer:

a) 112

b) 4

c) x=16 , y=12

Step-by-step explanation:

a) Given, x^2-y^2=112

x^2-y^2 = (x+y)(x-y) = 112

b) (x+y)(x-y) = 112. , given x+y = 28

28(x-y) = 112

x-y = 112/28 = 4

c) x+y = 28, x-y = 4

add both, 2x = 32

x=16

and x+y=28

y= 28-16

y=12