Question

sum of two numbers is 29 and one number exceeds another by 5. find the numbers​

Answer 1

Answer:

let one number be x

other number be x+5

According to the question,

x+x+5=29

=)2x=29-5

=)2x=24

x=12

x+5=17

Answer 2

$\huge\pink{\mathbb{ANSWER:- }}$

We have a puzzle here. We don't know the numbers.

We have to find them.

Let the smaller number 'x', then the bigger number will be 'x+5".

But it is given that sum of these two numbers is 29

⇒ x+x+5=29

⇒ 2x+5=29

∴ 2x=29−5

∴ 2x=24

x= 24/2

(Transposing '2' to RHS)

x=12

Therefore smaller number =x=12 and

Bigger number =x+5=12+5=17

Thus the required numbers are 12 and 17