sum of two numbers is 29 and one number exceeds another by 5 . find the numbers
Answers
Answered by
1
Answer:
here is your answer
Step-by-step explanation:
We have a puzzle here. We don't know the numbers. We have to find them.
Let the smaller number 'x', then the bigger number will be 'x+5".
But it is given that sum of these two numbers is 29
⇒ x+x+5=29
⇒ 2x+5=29
∴ 2x=29−5
∴ 2x=24
x=
2
24
(Transposing '2' to RHS)
x=12
Therefore smaller number =x=12 and
Bigger number =x+5=12+5=17
Thus the required numbers are 12 and 17
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Answered by
0
let the two numbers be a ,a+5
sum is 2a+5=29
2a=24
a=12
the numbers are 12 ,17
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