Question

sum of two Numbers is 29 and one numbers exceed another by 5 .find the numbers​

Answer 1

The two numbers are :

• The one number = 17.
• The other number = 12.

Given :

• The sum of two numbers = 29.
• One number exceed another number by 5.

To Find :

• The numbers.

Solution :

Let,

The other number be x.

The one number be x + 5 because according to the question, one number exceed another number by 5.

Given,

The sum of both numbers = 29

That means,

$: \implies \rm x +( x + 5) = 29 \\ \\ : \implies \rm x + x + 5 = 29 \\ \\ : \implies \rm 2x + 5 = 29 \\ \\ : \implies \rm 2x = 29 - 5 \\ \\ : \implies \rm2x = 24 \\ \\ : \implies \rm x = \dfrac{24}{2} \\ \\ : \implies \rm x = 12 \\ \\ \: \: \: \therefore \rm \: \: x = 12 \\ \\ \sf{So \: the \: numbers \: are : } \\ \\ \large{ \star} \: \: \small{ \sf The \: one \: number = x + 5 = 12 + 5 = 17 }\\ \large{ \star} \: \: \small{ \sf The \: other \: number = x = 12}$

Hence,

The two numbers are 17 and 12.

Verification :

Sum of both numbers is 29.

Now we have,

• The one number (x + 5) = 17.

• The other number (x) = 12.

$:\implies \rm x + x + 5 = 29 \\ \\ :\implies \rm 12 + 17 = 29 \\ \\ :\implies \rm 29 = 29$

Hence Verified !

Answer 2

Step-by-step explanation:

Hope it Helps...

let no. be x and x+5

so, x+(x+5)=29

x+x+5=29

2x=29-5

2x=24

x=12

x+5=12+5=17