Question

Sum of two numbers is 29and one number exceeds another by 5 ,find the numbers

Answer 1

Answer:

12 & 17

Step-by-step explanation:

Let one no be x and other number be x+5

X+X+5=29

2x=24

X=12

So numbers are x=12

X+5=12+5=17

Answer 2

$\large\bold\green{☑Verified Answer:-}$

$\huge\mathsf\blue{Solution:-}$

We have a puzzle here . We don't know numbers. We have to find them. Let the smaller number be 'x', then the bigger number will be 'x+5'.

But it is given that sum of these two numbers is 29.

$x + x + 5 = 29 \\ 2x + 5 = 29 \\ 2x = 29 - 5 \\ 2x = 24 \\ x = \frac{24}{2} \: (transposing \: 2 \: to \: RHS) \\ x = 12 \\ therefore \: smaller \: number = x = 12 \: and \\ bigger \: number \: = x + 5 = 12 + 5 = 17.$

Check:-

• 17 Exceeds 12 by 5 and their sum = 12+17=29