Question

Sum of two numbers is 3/4 an one of the number is 1/8. Find the other number.​​

Answer 1

Step-by-step explanation:

Let the other number be x then x+ 1/8=3/4=>

x+ 1/8=3/4 =>x+ 1/8=6/8 =>x=5/8. Hope it helps you.

Answer 2

Answer:

$\large \underline{\boxed{\mathsf{First \: number = \dfrac{5}{8}}}}$

Step-by-step explanation:

$\large \underline{\underline{\textbf{Given that...}}}$

Sum of two numbers is 3/4 and one number is 1/8. We need to find the other number .

$\large \underline{\underline{\textbf{Solution....}}}$

Now let ,

$\textsf{The number b '<strong>x</strong>'}$

and

$\mathsf{Second \:number \:= \dfrac{1}{8} \:\:\: \:\:\:\:\: (Given)}$

Therefore According to the question we have

Sum of First and second number = 3/4

That is $\implies$

$\mathsf{x + \dfrac{1}{8} = \dfrac{3}{4}}$

Now to solve, this type of equations we need to bring variables to one side and constants to other side ie- LHS and RHS .

$\large \boxed{\bigstar \:\: \mathsf{ \underbrace{x + y}_{LHS}=\underbrace{a +b}_{RHS}\:\:\bigstar }}$

So here

If we take (+1/8) from LHS to RHS it will change to (-1/8) .

That is

$\mathsf{x = \dfrac{3}{4} -\dfrac{1}{8} }$

Now solving RHS by taking LCM of 3/4 and 1/8. we have....

$\mathsf{x = \dfrac{(2 \times 3) - 1}{8}}$

$\implies \mathsf{x = \dfrac{5}{8}}$

$\underline{\textbf{ Therefore required answer is}}$

$\underline{\boxed{\mathsf{x = \dfrac{5}{8}}}}$