Question

Sum of two numbers is 32 Their difference is 8 Find those numbers​

Answer 1

Answer:

The two numbers are

20 and 12.

Solution:

Let the two numbers be x and y (x > y)

By the given conditions,

sum of the numbers = 32,

then x + y = 32 ..... (1)

and difference of the numbers = 8

then x - y = 8 ..... (2)

Now adding both (1) and (2) no. equations, we get

x + y + x - y = 32 + 8

or, 2x = 40

or, x = 20

From (1), we get

20 + y = 32

or, y = 32 - 20

or, y = 12

Therefore the two numbers are

20 and 12.

Answer 2

Answer:

Hey friend,

Here is the answer you are searching for,

Let numbers be x, y

A.T.Q,

x-y = 8

=> y = x-8

Also,

x+y = 32

By taking y as x-8,

x+y = 32

=> x+x-8 = 32

=> 2x = 40

=> x = 20

=> y = 20-8 = 12

Therefore,

Numbers = 20,12.

HOPE IT HELPS YOU.

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