Sum of two numbers is 40 and one number exceeds another number by 10. Find the numbers?
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3
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The numbers are 15 and 25.
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Answer:Let the first number be xsecond number be (x+10) // one exceed other by 10 //sum of the number is given by x+(x+10) = 40x+x+10=402x+10 = 402x =40-102x = 30x=30/2x=15first number x=15, second number x+10 = 15+10= 25The numbers are 15 and 25.
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