Question

sum of two numbers is 40.If one of them is 10 more than the other,find the number

Answer 1

let the common factor be x.
x+x+10=40
2x+10=40
2x=30
x=30/2=15.
Therefore the numbers are x=15
x+10=15+10=25.
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Answer 2

Let one of the numbers be x
The other number = x + 10
Therefore we get a linear equation
40= x +x+10
40-10= 2x
30=2x
30/2=x
15=x
 one number is x and other is x+10
therefore the first number is 15 and the second one is (x+10=15+10=25)  25