Math, asked by amaraganinikhilsai, 1 month ago

Sum of two numbers is 45 and one number
exceeds another by 9. Find the numbers​

Answers

Answered by DDR108
61

Answer:

let the 1st no. be a

2nd no.= a+1

According to question

a+1+a=45

2a=44

a=22

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Answered by srivastavaabhisek826
0

Step-by-step explanation:

  • Sum of the two number = 45
  • let the number be x
  • Another number is exceeds by 9 =X+9

To find:- find the both number whose sum is 45

Solution:-

x + x + 9 = 45 \\ 2x + 9 = 45 \\ 2x = 45 - 9 \\ 2x = 36 \\ x =  \frac{36}{2}  = 18 \\

First number is 18

And second number is X+9 = 18+9 =27

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