Sum of two numbers is 67. If one number exceeds the other by 12, find the numbers
Answers
Answer:
the first no. is 27.5
the second no. is 39.5
Step-by-step explanation:
Let the first no. be x
So , Acc. to question
the second no be. 12+x
Therefore, the equation be = x+(x+12) =67
= 2x+12=67
=2x=67-12
=2x=55
= x=55/2
= x= 27.5
Hence , the first no. is x= 27.5
the second no. is 12+x.
= 12+27.5
= 39.5
Check, 27.5+39.5 = 67
Given: sum of two numbers = 67
one number exceeds the other by 12
Let the first number be x and the second number be x+12
According to the condition given to us:
x+ x+ 12= 67
2x+12= 67
2x = 55
x= 55/2
= 27.5
The first number will be x= 27.5
The second number will be x+12= 39.5