Sum of two numbers is 80 and the greater number exceeds twice the smaller by 11
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Answered by
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Step-by-step explanation:
Let the smaller number be x
Then the bigger will be 11 + 2x
A/q,
=> 11 + 2x + x = 80
=> 3x = 80-11
=> x = 69
=> x = 23 ans.
And, also 11 + 2x = 11 + 46 = 57 ans.
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