Question

sum of two numbers is 84. one of the numbers is 20 more than the other. the smaller number is​

Answer 1

Answer:

32 and 52

Step-by-step explanation:

let x+ y=84

x=y+20

x+y=84

y+20+y=84

2y=84-20

2y=64

y=32

x=y+20

x=32+20

x=52

therefore the two nos. are 32 and 52.

Answer 2

Answer:

The smaller number is 32 and the larger number is 52

Step-by-step explanation:

Let the smaller number = x

So, the larger number will be = x + 20

The sum of the two numbers = 84

So,  x + x + 20 = 84

      2x + 20 = 84

      2 ( x + 10 ) = 84

          x + 10 = 84 / 2

          x + 10 = 42

           x = 42 - 10

           x = 32

The smaller number is 32

The larger number is 32 + 20 =52

Check

x + x + 20 should be equal to 84

Putting values of the two numbers, we get

32 + 52 = 84