Math, asked by mousumisaha958, 1 month ago

Sum of two numbers is 95. If one exceeds of the other by 15, Find the two numbers, please answer it fast

Answers

Answered by Aish112009
1

Answer:

Let one of the numbers be= x.

Then, the other number becomes x + 15

According to the question,

x + x + 15 = 95

⇒ 2x + 15 = 95

⇒ 2x = 95 - 15

⇒ 2x = 80

\Rightarrow x=\frac{80}{2}⇒x=

2

80

⇒ x = 40

First number = x = 40

And, other number = x + 15 = 40 + 15 = 55

Answered by KnightLyfe
26

Answer:

40 and 55.

Step-by-step explanation:

As per the provided information in the given question, we have:

  • Sum of two numbers = 95
  • Second number exceeds the other by 15.

Let us suppose the first number as 1x and the second number as x+15.

Now, according to the question, the sum of two numbers is 95. According to our assumption,

\longrightarrow\quad\sf{Sum\: of\: two\: numbers=x+x+15}

Here, the sum of two number is 95, so equating this value.

\longrightarrow\quad\sf{95=x+x+15}

Performing addition.

\longrightarrow\quad\sf{95=2x+15}

Transposing 15 from RHS to LHS.

\longrightarrow\quad\sf{95-15=2x}

Performing subtraction.

\longrightarrow\quad\sf{80=2x}

Transposing 2 from RHS to LHS.

\longrightarrow\quad\sf{\dfrac{80}{2}=x}

\longrightarrow\quad\bold{x=40}

We've calculated the value of x that is 40. As we have assumed that the second number as x+15. Thus, Substituting value of x in the second number.

\longrightarrow\quad\sf{Second\: number=40+15}

Performing addition.

\longrightarrow\quad\bold{Second\: number=55}

❝ Therefore, the two numbers are 40 and 55. ❞

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