Sum of two numbers is 95. If one exceeds the orther by 15, find the numbers.
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let the first number be x
the other number be x+5
sum of the number 95
x+x+5=15
2x+15=95
2x=95-15=80
2x=80
x=80
2. = 40
therefore first number =40
second number be =40+15=55
the other number be x+5
sum of the number 95
x+x+5=15
2x+15=95
2x=95-15=80
2x=80
x=80
2. = 40
therefore first number =40
second number be =40+15=55
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