Sum of two numbers is 95 if one exceeds the other bt 15 find thw number
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Answered by
6
Let the 1st number be x
Given, one number exceeds the another by 15 => x + 15
Given, their sum => 95
A/q,
x + x + 15 = 95
2x + 15 = 95
2x = 95 - 15
2x = 80
x =
x = 40
1st number => x => 40
2nd number => x + 15 => 40 + 15 => 55
The numbers are 40 and 55
#BeBrainly
vikram99192:
genius great di
Answered by
2
Let,
One number be x.
Another number is (x+15).
So,
x + (x + 15) = 95
x + x + 15 = 95
2x + 15 = 95
2x = 95 - 15
2x = 80
x = 80/2
x = 40
Therefore, one number x is . And another number is (x+15) = 40 + 15 = .
One number be x.
Another number is (x+15).
So,
x + (x + 15) = 95
x + x + 15 = 95
2x + 15 = 95
2x = 95 - 15
2x = 80
x = 80/2
x = 40
Therefore, one number x is . And another number is (x+15) = 40 + 15 = .
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