Sum of two numbers is 95. If one exceeds the other by 15 find the
numbers.
Answers
Answered by
1
Answer:
Solution :
First number be X
Second number be X + 1
If first number exceeds = X + 15
second number exceeds =( X+1 ) +15
Total sum be 95
Now equation be X+15 +X+16 =95
so 2X + 31 =95
2X = 95 - 31
2X = 64
X = 64 / 2
so X = 32
Now first number is X + 15 = 32 + 15 = 47
second number is X + 16 = 32 + 16 = 48
47 , 48 are the two numbers
Answered by
22
☆ Solution ☆
⟹ Sum of two no. = 95
⟹ Let 1st no. be = x
⟹ And another no. be = x + 15
☆ According to the Question ☆
⟹ Sum of no. = 95
⟹ x + ( x + 15 ) = 95
⟹ 2x + 15 = 95
⟹ 2x = 95 - 15
⟹ 2x = 80
⟹ x = 80/2 = 40
★ Ans → 1st no. x = 40,2nd no. = x + 15
= 40 + 15
= 55.
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