Sum of two numbers is 95 . If one exceeds the other by 15 , find the number ?
Answers
Step-by-step explanation:
Take the first integer as
x
. Since we are talking about the next even integer, it will come when you add two to
x
.
For example, let's say that you have
2
as the value of
x
. The next even integer is
4
, which is
x
+
2
, and the next is
6
, which is
x
+
4
.
So eventually, the equation is
(
x
)
+
(
x
+
2
)
+
(
x
+
4
)
=
66
3
x
+
6
=
66
3
x
=
66
−
6
3
x
=
60
x
=
60
÷
3
x
=
20
So
x
=
20
x
+
2
=
22
x
+
4
=
24
Given :-
Sum of two numbers = 95
Second number exceeds by 15.
To Find :-
The first number.
The second number.
Analysis :-
Consider them as variables.
Make an equation accordingly.
Then find the first number and the second one as well.
Solution :-
Let one of the numbers be= x. Then, the other number becomes x + 15.
Given that,
Sum of two numbers = 95
Making an equation,
x + x + 15 = 95
2x + 15 = 95
By transposing,
2x = 95 – 15
2x = 80
Finding x,
x = 80/2
x = 40
Other number = x + 15
= 40 + 15 = 55
Therefore, the two numbers are 40 and 55.