Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.
Answers
Answer:
First number = 40
Second number = 55
Step-by-step explanation:
Let us consider,
First number = x
Second number = x + 15...(Because it exceeds
first be 15)
x + x + 15 = 95
2x + 15 = 95
2x = 95 - 15
2x = 80
x = 80/2
x = 40
Therefore,
First number = x = 40
Second number = x + 15 = 40 + 15 = 55
✪ Question ✪
Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.
✪ Given ✪
- Sum of two numbers is 95.
- One exceeds the other by 15.
✪ To find ✪
The numbers.
✪ Solution ✪
Let the smaller number be x.
So, larger number = (x+15)
∴ x + (x+15) = 95
⇒ x + x + 15 = 95
⇒ 2x + 15 = 95
⇒ 2x = 95 - 15
⇒ 2x = 80
⇒ x = 80/2
⇒x = 40
✪ Hence ✪
x = 40
Smaller number = x = 40
Larger number = (x+15) = (40+15) = 55
✪ Therefore ✪
The numbers are 40 and 55.
------------------------------------------------------------
✪ Verification ✪
x + (x+15) = 95
⇒ 40 + 55 = 95
⇒ 95 = 95
So, L.H.S = R.H.S.
Hence, verified.
๑ Hope this helps you. ๑