Math, asked by jiteshchichole123, 5 months ago

Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.​

Answers

Answered by RushikeshS9763
3

Answer:

First number = 40

Second number = 55

Step-by-step explanation:

Let us consider,

First number = x

Second number = x + 15...(Because it exceeds

first be 15)

x + x + 15 = 95

2x + 15 = 95

2x = 95 - 15

2x = 80

x = 80/2

x = 40

Therefore,

First number = x = 40

Second number = x + 15 = 40 + 15 = 55

Answered by Anonymous
3

✪ Question ✪

Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.

✪ Given ✪

  • Sum of two numbers is 95.
  • One exceeds the other by 15.

✪ To find ✪

The numbers.

✪ Solution ✪

Let the smaller number be x.

So, larger number = (x+15)

∴ x + (x+15) = 95

⇒ x + x + 15 = 95

⇒ 2x + 15 = 95

⇒ 2x = 95 - 15

⇒ 2x = 80

⇒ x = 80/2

⇒x = 40

✪ Hence ✪

x = 40

Smaller number = x = 40

Larger number = (x+15) = (40+15) = 55

✪ Therefore ✪

The numbers are 40 and 55.

------------------------------------------------------------

✪ Verification ✪

x + (x+15) = 95

⇒ 40 + 55 = 95

⇒ 95 = 95

So, L.H.S = R.H.S.

Hence, verified.

๑ Hope this helps you. ๑

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