Question

Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.5.Two numbers are in the ratio 5:3. If they differ by 18, what are the numbers?​

Answer 1

Question 1 :-

• Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.

Answer :-

• The numbers are 40 and 55.

Solution :-

• Let the first number be "x".

Then :-

• The second number will be "x + 15" as it exceeds the first number by 15.

Now, it is given that :-

• The sum of these two numbers is 95.

Therefore,

$\longmapsto \bf x + x + 15 = 95$

$\bf\longmapsto 2x + 15 = 95$

$\bf\longmapsto 2x = 95 - 15$

$\bf \longmapsto 2x = 80$

$\longmapsto \bf x = \dfrac{80}{2}$

$\longmapsto \underline{ \boxed{ \bf x = 40}}$

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Hence, the numbers are :-

$\sf x = 40.$

$\sf x + 15 = 40 + 15 = 55.$

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Question 2 :-

• Two numbers are in the ratio 5 : 3. If they differ by 18, what are the numbers?

Answer :-

• The numbers are 45 and 27.

Solution :-

• Let the numbers be 5x and 3x, as they are in the ratio 5 : 3.

It is given that :-

• They differ by 18.

Therefore,

$\longmapsto \bf 5x - 3x = 18$

$\bf\longmapsto 2x = 18$

$\longmapsto \bf x = \dfrac{18}{2}$

$\longmapsto \underline{ \boxed{\bf x = 9}}$

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Hence, the numbers are :-

$\sf5x = 5 \times 9 = 45.$

$\sf3x = 3 \times 9 = 27.$

Answer 2

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