Sum of two numbers is 95. If one exceeds the other by 15, find the numbers
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Sum of two numbers is 95. If one exceeds the other by 15, find the numbers. Let the first number be x, then another number be x + 15. And another number = 40 + 15 = 55.
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Q4) Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.
Solution:
Sum of two number = 95
Let the first number be x, then another number be x + 15.
According to the question, x + x + 15 = 95
\Rightarrow2x+15=95⇒2x+15=95
\Rightarrow2x+15-15=95-15⇒2x+15−15=95−15
[Subtracting 15 from both sides]
\Rightarrow2x=80⇒2x=80
\Rightarrow\ \frac{2x}{2}=\frac{80}{2}⇒
2
2x
=
2
80
[Dividing both sides by 2]
\Rightarrow\ x=40⇒ x=40
Hence, the first number = 40
And another number = 40 + 15 = 55.
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