Question

Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.​

Answer 1

Answer:

Given :-

• Sum of two numbers is 95.
• One exceeds the other by 15.

To Find :-

• What are the numbers.

Solution :-

Let,

$\leadsto \bf{First\: number =\: y}$

$\leadsto \bf{Second\: number =\: y + 15}$

Given :

$\bullet$ Sum of two numbers is 95.

According to the question,

$\implies \sf y + y + 15 =\: 95$

$\implies \sf 2y + 15 =\: 95$

$\implies \sf 2y =\: 95 - 15$

$\implies \sf 2y =\: 80$

$\implies \sf y =\: \dfrac{\cancel{80}}{\cancel{2}}$

$\implies \sf y =\: \dfrac{40}{1}$

$\implies \sf\bold{\purple{y =\: 40}}$

Hence, the required numbers are :

➲ First Number :

$\longrightarrow \sf First\: number =\: y$

$\longrightarrow \sf\bold{\red{First\: number =\: 40}}$

➲ Second Number :

$\longrightarrow \sf Second\: number =\: y + 15$

$\longrightarrow \sf Second\: number =\: 40 + 15$

$\longrightarrow \sf \bold{\red{Second\: number =\: 55}}$

${\small{\bold{\purple{\underline{\therefore\: The\: numbers\: are\: 40\: and\: 55\: .}}}}}$

Answer 2

$\large \purple \star \: \underline \bold\red {given : - }$

$\bold { \: \: \: \: \: \: \: \: \: \: Sum \: \: of \: \: two \: \: numbers \: \: is \: \: 95 \: }$

$\bold { \: \: \: \: \: \: \: \: \: \: one \: \: \: exceeds \: \: the \: \: other \: \: by \: \: 15 }$

$\large \purple \star \: \underline \bold\green {To \: \: Find \: : - }$

$\bold { \: \: \: \: \: \: \: \: \: \: what \: \: are \: \: the \: \: numbers }$

$\large \purple \star \: \underline \bold\blue {Solution\: : - }$

$\bold\blue {Let\: \: the\: \: two \: \:numbers\: \: be \: \:x \: \:and\: \: y }$

$\bold\purple { It \: \:is\: \: given\: \: that \: \:one \: \:exceeds\: \: the \: \:other\: \: by\: \: 15\: }$

$\bold\red { So, \: \:y\: \: =\: \: (\: \:x\: \:+\: \:15)\: }$

$\bold \pink { \: Sum \: \:of \: \:two \: \:numbers\: \: =\: \: 95\: }$

$\bold { ⇢x+y=95 -----(1)}$

$\bold { ⇢ x + (x+15) = 95 }$

$\bold { ⇢ 2x= 95-15 }$

$\bold { ⇢ 2x = 80 }$

$\bold\green { ⇢x = 40 }$

$\bold \red { Put\: \: (x=40)\: \: in \: \:equation\: \: (1) \: \:we \: \:will\: \: get, }$

$\bold { ⇢ 40+ y = 95 }$

$\bold { ⇢ y=95-40 }$

$\bold \pink{ ⇢y = 55 }$

$\bold\blue { ∴ Required\: \: two \: \: numbers\: \: are \: \: 40 \: \: and \: \: 50 }$