Question

Sum of two numbers is 95. If one exceeds the other by 3, find the numbers.
Sum of three consecutive integers is 24. Find the integers.​

Answer 1

$\huge \color{red}{answer}$

finally a good question asked on this app

Btw here is your answer

let number be x

so according to question

one exceed s other by 3 ie x = x + 3

ie one number is x and other is x +3

so according to question

x + x + 3 = 95

2x + 3 = 95

2x = 95 - 3

2x = 92

x = 46

now one number is 46 and other is x +3 ie 46 + 3 = 49

so two numbers are 46 and 49

Now 2nd one

1st we need to know about what are integers

so integers are number which has numerator as 1

then consicutive means one after another

so if 1 inter is x then other will be x + 1 and x +2

now according to question

x + x + 1 + x + 2 = 24

3x + 3 = 24

3x = 24 - 3

3x = 21

x = 7

now integers are 7 also x +1 = 7 + 1 = 8 and x +2 = 7 + 2 = 9

so integers are 7 8 and 9

hope it helps you

be brainly

Answer 2

$\tt\large\underline\purple{Question-(1)}$

$\sf\large\underline{Let:-}$

$\tt{\implies Other\:number=x}$

$\tt{\implies First\: number=x+3}$

$\sf\large\underline{Given:-}$

$\tt{\implies Sum\:_{(First+other)}=95}$

$\sf\large\underline{To\: Find:-}$

$\tt{\implies The\:numbers=?}$

$\sf\large\underline{Solution:-}$

$\tt{\implies Sum\:of\: number\:_{(First+other)}=95}$

$\tt{\implies x+3+x=95}$

$\tt{\implies 2x+3=95}$

$\tt{\implies 2x=95-3}$

$\tt{\implies 2x=92}$

$\tt{\implies x=46}$

$\sf\large{Hence,}$

$\tt{\implies First\: number=x+3=46+3=49}$

$\tt{\implies Other\: number=x=46}$

$\tt\large\underline\purple{Question-(2)}$

$\sf\large\underline{Let:-}$

$\tt{\implies The\: integers=x}$

$\tt{\implies First\: integer=x}$

$\tt{\implies second\: integer=x+1}$

$\tt{\implies Third\: integer=x+2}$

$\sf\large\underline{Given:-}$

$\tt{\implies Sum\:_{(first+second+third)}=24}$

$\sf\large\underline{To\: Find:-}$

$\tt{\implies The\: integers=?}$

$\sf\large\underline{Solution:-}$

$\tt{\implies Sum\:of\: integers\:_{(first+second+third)}=24}$

$\tt{\implies x+x+1+x+2=24}$

$\tt{\implies 3x+3=24}$

$\tt{\implies 3x=24-3}$

$\tt{\implies 3x=21}$

$\tt{\implies x=7}$

$\sf\large{Hence,}$

$\tt{\implies First\:integer=x=7}$

$\tt{\implies Second\: integer=x+1=7+1=8}$

$\tt{\implies Third\: integer=x+2=7+2=9}$