sum of two numbers is 95 if one exceeds The Other by 3, find the numbers
Answers
Answered by
14
x+(x+3)=95
2x+3=95
2x=95-3
2x=92
x=92/2
x=46
x+3=46+3=49
verification
x+(x+3)=95
46+(46+3)=95
46+49=95
95=95
lhs =rhs
proved
2x+3=95
2x=95-3
2x=92
x=92/2
x=46
x+3=46+3=49
verification
x+(x+3)=95
46+(46+3)=95
46+49=95
95=95
lhs =rhs
proved
Answered by
0
Answer:
46 and 49
Step-By-Step Explanation:
Let one of the numbers be= x.
Then, the other number becomes x + 3
According to the question,
x + x + 3 = 95
⇒ 2x + 3 = 95
⇒ 2x = 95 – 3
⇒ 2x = 92
⇒ x = 92/2
⇒ x = 46
First number = x = 46
And, other number = x + 3 = 46 + 3 = 49
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