sum of two numbers is 95. if one exceeds the other by 3 find the numbers
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Answered by
18
Let the first number be a
Second number = a + 3
According to question,
a + a + 3 = 95
=> 2a + 3 = 95
=> 2a = 92
=> a = 46
First number = 46
Second number = 49
Second number = a + 3
According to question,
a + a + 3 = 95
=> 2a + 3 = 95
=> 2a = 92
=> a = 46
First number = 46
Second number = 49
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Answered by
10
Let the no.s be x and y
x + y=95
x=y+3
so, x+ y= y+3 +y= 2y + 3
2y = 95-3=92
y =46
x=46+3=49
x + y=95
x=y+3
so, x+ y= y+3 +y= 2y + 3
2y = 95-3=92
y =46
x=46+3=49
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