Question

Sum of two numbers is 95 . If one exeeds the other by 3, find the numbers​

Answer 1

Answer:

Let the one number be x and the other number be y.

It is given that the sum of the numbers is 95, therefore, we have:

x+y=95....(1)

It is also given that one number exceeds the other by 3 which means:

x=y+3

⇒x−y=3....(2)

Now, we add equations 1 and 2 as follows:

x+y+x−y=95+3

⇒(x+x)+(y−y)=98

⇒2x=98

⇒x=

2

98

⇒x=49

Now, substitute the value of x in equation 2 to find the value of y as shown below:

x−y=3

⇒49−y=3

⇒y=49−3

⇒y=46

Therefore, the two numbers are x=49 and y=46 and the product of the numbers is:

x×y=49×46=2254.

Hence, the product of the numbers is 2254.

Answer 2

Let the one number be x and the other number be y.

It is given that the sum of the numbers is 95, therefore, we have:

x+y=95....(1)

It is also given that one number exceeds the other by 3 which means:

x=y+3

⇒x−y=3....(2)

Now, we add equations 1 and 2 as follows:

x+y+x−y=95+3

⇒(x+x)+(y−y)=98

⇒2x=98

⇒x=

2

98

⇒x=49

Now, substitute the value of x in equation 2 to find the value of y as shown below:

x−y=3

⇒49−y=3

⇒y=49−3

⇒y=46

Therefore, the two numbers are x=49 and y=46 and the product of the numbers is:

x×y=49×46=2254.

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