Question

Sum of two numbers is 98.If one number is 16 more than the other, the number are

Answer 1

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Sum of two numbers is 98.If one number is 16 more than the other, the number are

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Let the first number be 'x'

Second number be x+16

According to the question:--

$= > x + x + 16 = 98$

$= > 2x + 16 = 98$

$= > 2x = 98 - 16$

$= > 2x = 82$

$= > x = 41$

$\bold{First\: number\: is\:{\red{ 41 }}}$

$\bold{second\: number\: =x+16=41+16={\blue{57}}}$

Therefore,The number are (41,57)

$\bold{sum = 41 + 57 = 98}$

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Answer 2

Answer-/

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Here , Let the first number be " X "

Now , Second number will be ( X + 16 )

According to the question / -

( X + 16 ) + X = 98

= > X + X + 16 = 98

= > 2X + 16 = 98

= > 2X = 98 - 16

= > 2X = 82

= > X = 41

Hence , the first number will be 41 .

Now , the second number will be / -

= ( X + 16 )

= ( 41 + 16 )

= 57

Hence , the second number will be 57 .

Therefore , the two numbers are 41 and 57 .

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