sum of two numbers is equal to 10 . if the sum their reciprocal is 5/8 .find the numbers
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LET FIRST NO BE X AND SECOND BE Y
ACCORDING TO 1ST CONDITION
X+Y = 10...
X=10-Y ...(1)
ACCORDING TO 2ND CONDITION
1/X+1/ Y =5/8
LET X= 10-Y
1/10-Y+1/Y=5/8
10-Y+Y/Y(10-Y) = 5/8
10/10Y-Y²=5/8
80= 50Y-Y²
Y²-50Y+80=0
SOLVE AFTER BY FACTORIZATION METHOD
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