Math, asked by brain167, 1 month ago

sum of two numbers is nine and there difference is also nine . find the numbers.
the easy and correct method as well as answer will get the brain list mark...

Answers

Answered by riya7776
2

Answer:

Let the ten's digit no. be x and one's digit no. be y.

Let the ten's digit no. be x and one's digit no. be y.So the no. will be = 10x+y.

Let the ten's digit no. be x and one's digit no. be y.So the no. will be = 10x+y.Given : x+y=9-----(I)

Let the ten's digit no. be x and one's digit no. be y.So the no. will be = 10x+y.Given : x+y=9-----(I) 9(10x+y)=2(10y+x) ⇒88x−11y=0 -----(II)

Let the ten's digit no. be x and one's digit no. be y.So the no. will be = 10x+y.Given : x+y=9-----(I) 9(10x+y)=2(10y+x) ⇒88x−11y=0 -----(II)On solving I and II simultaneously you will get x=1 and y=8.

Let the ten's digit no. be x and one's digit no. be y.So the no. will be = 10x+y.Given : x+y=9-----(I) 9(10x+y)=2(10y+x) ⇒88x−11y=0 -----(II)On solving I and II simultaneously you will get x=1 and y=8.Therefore your desired no. is 18.

Answered by Anonymous
1

solutions:

➣Let the ten's digit no. be x and one's digit no. be y.

➣So the no. will be = 10x+y.

➣Given : x+y=9-----(I)

➣9(10x+y)=2(10y+x) ⇒88x−11y=0 -----(II)

➣On solving I and II simultaneously you will get x=1 and y=8.

Therefore your desired no. is 18.

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