Question

Sum of two numbers is ten and their difference is six. Find the
numbers.​

Answer 1

Concept:

A simultaneous equations in two variables are formed as per given data.

The solution of those equations is found by elimination method.

Let the two numbers be x and y with x > y

As per given data,

x + y = 10.........(1)

x - y = 6............(2)

(1)+(2)

2x = 16

x = 16/2

x = 8

put x = 8 in (1)

x + y = 10

8 + y =10

y = 10 - 8

y = 2

Solution: x = 8, y = 2

Answer 2

Answer:

The two numbers are 8 and 2

Step-by-step explanation:

Given

Sum of two numbers is ten and their difference is six.

Let x and y be the two numbers.

∴Sum of x and y = 10

⇒x + y = 10

difference of x and y = 6

⇒x - y = 6

Adding the sum of x and y and difference of x and y

(x+y) + (x-y) = 10 +6

2x = 16

x =  16/2

∴ x = 8

finding y

from x +y = 10

 on substituting the value of x = 8 , we get

8 + y  = 10

y = 10 - 8

∴ y = 2

Therefore the two numbers are 8 and 2

The project code is #SPJ2.