Question

Sum of two numbers is $\dfrac{3}{4}$ ,one of the number is $\dfrac{1}{8}$ find the other..​

Answer 1

Answer:

Let the other number be x

$\implies$ x + $\dfrac{1}{8 }$ = $\dfrac{3}{4}$

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$\implies$ x = $\dfrac{3}{4}$ - $\dfrac{1}{8}$

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$\implies$ x = $\dfrac{3 × 2}{4 × 8}$ - $\dfrac{1}{8}$

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$\implies$ x = $\dfrac{6}{8}$ - $\dfrac{1}{8}$

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$\implies$ x = $\dfrac{6 - 1}{8}$

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$\implies$ x = $\dfrac{5 }{8}$