Question

sum of two numbers is thrice a number and difference is 40 find the ans
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Answer 1

Step-by-step explanation:

Here's what we know:

a + b = 20

3a - 2b  = 40

We can solve this with the elimination method. Multiply the first equation by 2:

2a + 2b = 40

3a - 2b = 40

5a = 80

Divide by 5:

a = 16

Now we can find b:

16 + b = 20

b = 4

check:

16 * 3 - 2 * 4 = 40

48 - 8 = 40

40 = 40