Question

Sum.Of two oppositeangle of a parallelogram is 130. Find the measure of each angle

Answer 1

Answer:65°

Step-by-step explanation:let, the angles be x° each

∴2x=130°

⇒x=65°

∴each angle = 65°

Answer 2

$\huge\red{Hi\: Friend}$

Here is your answer

Let the ABCD is parallelogram

/_A + /_C = 130

As opposite angles of the parallelogram is equal hence
/_ A = /_ C = 130/2 = 65°

Now
Let. /_B = /_D = x °

As Sum of all angles of a parallelogram is 360
$x + x + 130 = 360 \\ 2x = 360 - 130 \\ 2x = 230 \\ x = \frac{230}{2} \\ x = 115$
Therefore each angles of the parallelogram are
/_ A = 65°
/_ B = 115°
/_ C = 65°
/_ D = 115°

$<marquee>Hope it helps you$