Question

sum of two zeroes of the polynomial x^3+500x^2+800x+d is 400. Find its third zero

Answer 1

I have mentioned my answer above please Mark me as brainliest

Answer 2

Answer:

value of third root is : - 900

Step-by-step explanation:

Given :- $x^3 + 500x^2 + 800x + d$  , sum of two roots is 400

To find out :- value of third root .

Solution :-

Step 1)  By comparing with standard eqn , a = 1 , b = 500 , c = 800 .

Step 2) we know the sum of the roots is = -b/a

Therefore , α+β+∝= -b/a

α+β = 400 , (given )

Thus ,

400 + ∝ = -(500/1)

∝ = -500 - 400 = -900

therefore , value of third root is : - 900

#SPJ3