Question

sum of values of the polynomialp(x)=x⁴-3x²+2x-1 at x=1and x=2​

Answer 1

Given:

A polynomial p(x)= x⁴-3x²+2x-1

To Find:

Sum of values of given polynomial at x=1 and x=2

Solution:

To find the values given polynomial, we have to substitute x from 1 and 2 in the expression of polynomial,

For x= 1

$\mathrm{p(1)=(1)^{4}-3(1)^{2}+2(1)-1}$

$\mathrm{p(1)=1-3+2-1}$

$\mathrm{p(1)=3-4}$

$\mathrm{p(1)=-1}$

For x= 2

$\mathrm{p(2)=(2)^{4}-3(2)^{2}+2(2)-1}$

$\mathrm{p(2)=16-3(4)+4-1}$

$\mathrm{p(2)=16-12+4-1}$

$\mathrm{p(2)=20-13}$

$\mathrm{p(2)=7}$

Now,

Required Sum= p(1)+p(2)

Required Sum= -1+7

Required Sum= 6

Hence, the sum of values of the polynomial p(x)=x⁴-3x²+2x-1 at x=1 and x=2​ is 6.