Question

Sum of y co-ordinatespf points on curve y=x^4-x^2+2when curve is horizontal is

Answer 1

Answer:

here is your answer

Explanation:

Let (x,y) be the points.

Slop of the given line =−  

6

1

​  

 

∴  Slop of the point perpendicular to is =6

y=3x  

2

+4

Differentiate w.r.t x,

⇒    

dx

dy

​  

=6x

Slop of the tan gent at (x,y)=  

dx

dy

​  

=6x

Slope of the tangent at (x,y)= Slop of the given line.

⇒  6x=6

⇒  x=1

Now,  

⇒  y=3x  

2

+4=3(1)  

2

+4=3+4=7

∴  The required point is (1,7).

hope u understood...

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