Question

Sum of zeros=2, product of zeros=-3

Answer 1

Answer:

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Step-by-step explanation:

a quatric polynomial is in the form x^2+ ( alpha+ beta)x+ alpha* beta

alpha + beta will be = 2(sum of the zeros)

alpha *beta  will be = 3(product of zeros)

x^2 +(2)x+ 3

x^2+2x+3 is the quatric polynomial

Answer 2

$\huge{\boxed{\mathcal\pink{\fcolorbox{red}{purple}{.SoLUTioN :-.}}}}$

Let two zeros be x and y.

ATQ,

x+y= 2

=> x = 2-y ----(i)

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and

xy = 3

{now putting the value of x from equation (i) }

=> (2-y) y = 3

=> 2y - y² = 3

=> y² +2y -3 = 0

=> y² +3y - y -3 = 0

=> y(y+3) -1(y+3) =0

=> ( y - 1)(y+3)= 0

=> (y+3) = 0 ×1/(y-1)

=> y = 0-3

=> y = -3 -----(ii)

hence,

{putting the value of y in equation (i) }

x =2 -y

=> x = 2 -(-3)

=> x = 2+3

=> x = 5

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therefore those two zeroes are:-

1. ( -3)
2. (5)

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