Question

Sum of zeros in polynomial x2+4x+8 is

Answer 1

Answer:

Step-by-step explanation:

Given Sum of zeros in polynomial x2+4x+8 is

If we take a polynomial and then a factor out of it we may get

 f(x) = p(x - a)(x - b)(x - c) and so on

here the roots are a, b, c where the polynomial is zero.

Now consider a quadratic equation ax^2 + bx + c

By adding the roots will be - b/a

here b = 4 and a = 1

  = - b / a = - 4 /1

So sum of roots of polynomial is - 4

Answer 2

Answer:

The sum of zeros in polynomial x²+4x+8 is -4.

Step-by-step explanation:

The given polynomial is

$x^2+4x+8$

Using quadratic formula the zeroes of the polynomial are

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Sum of the zeroes is

$sum=\frac{-b+\sqrt{b^2-4ac}}{2a}+\frac{-b-\sqrt{b^2-4ac}}{2a}=\frac{-2b}{2a}=-\frac{b}{a}$

The sum of zeros in polynomial x²+4x+8 is

$-\frac{b}{a}=-\frac{4}{1}=-4$

Therefore the sum of zeros in polynomial x²+4x+8 is -4.