sum of zeros of 9x^2 =4?
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Step-by-step explanation:
Solution
We have,
9x2−5=(3x)2−(5)2=(3x−5)(3x+5)
So, the value of 9x2−5 is 0, when
3x−5=0 or 3x+5=0
i.e.,
when x=35 or x=3−5
Therefore, the zeros of 9x2−5 i.e. 35 and -5/3
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