Question

Sum sum of the digits of a two-digit number is 11 the given number is less than the number obtained by interchanging the digits by 9 find the number ​

Answer 1

Answer:

number is 56

Step-by-step explanation:

Two digit number: xy= 10x+y.

Sum of digits: x+y=11

xy is less then yx by 9: xy+9=yx

xy+9=yx

10x+y=10y+x-9

9x-9y=-9

x-y=-1,

So this is the system of equations to be solved:

x + y=11

x - y =-1

x=5, y=6

The number is 56.

hope its help you please make brainliest my answer

Answer 2

Answer:

56

Step-by-step explanation:

LET THE DIGIT AT ONE'S PLACE IS X

DIGIT AT TEN'S PLACE =11-X

ORIGINAL NO=X+10(11-X)

X+110-10X=110-9X

BY INTERCHANGING NO

DIGIT AT ONE'S PLACE=11-X

DIGIT AT TEN'S PLACE = X

11-X+10X=11+9X

ACCORDING TO QUESTION

110-9X=11+9X-9

110-11+9=9X+9X

108=18X

6=X

NO=110-9*6          (PUTTING VALUE IN ORIGINAL NO)

110-54=56