Sum the following series to n terms 3+5+9+15+23+----
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Answered by
1
Answer:
according to question :-
3+2 = 5
5+4 = 9
9+6 = 15
15+8 = 23
23+10 = 43 Answer
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Answered by
1
Given AP: 3 , 5 , 9 , 13 ....... where
- a = 3
- d = 4
- n = n terms.
Thus sum of all terms i.e. Sn = n/2 [ 2a + (n-1)d ]
Sn =
- (n/2)[2(3) + (n-1)4]
- (n/2)[6 + 4n -4]
- (n/2)(2n-4)
- (2)(n/2)(n-2)
- n(n-2)
- n² - 2n
Thus the sum of n terms of the given expression is n² - 2n for any natural number n.
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