Sum the series n.1+(1-1).2 + (n - 2).3 + ......+1.n
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the r th term will be r(n-r+1)
it is summation of r(n-r+1) where r varies from 1 to n;
SUM ( (n+1)r - r^2 ) = (n+1)(n)(n+1)/2 - (n)(n+1)(2n+1)/6
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