Question

sum to infinity terms of G.p, if r<1 is​

Answer 1

Answer:

sum of infinite G.p. is

a(1-r^n)/(1-r). where a is first term

Answer 2

Answer:

$\huge{\boxed{\sf{s \infty = \frac{a}{1 - r} (for |r| < 1) }}}$

Step-by-step explanation:

$\huge{\boxed{\sf{SOLUTION-}}}$

$\huge{\boxed{\sf{SUM\:OF\:INFINITE\:TERMS{(S\infty)}}}}$

$s \infty = \frac{a}{1 - r} (for |r| < 1) \\ > > note = when |r| \geqslant 1\\ the \: series \: is \: divegent \: and \\ so \: its \: sum \: is \: not \: possible$

$\huge{\boxed{\sf{s \infty = \frac{a}{1 - r} (for |r| < 1) }}}$