Question

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Sum to n terms the series whose nth term is
1^3 +2^3 +3^3 +...+n^3 / n​

Answer 1

Step-by-step explanation:

The answer is [n(n+1)/2]^2

Answer 2

Answer:

(x+1)^4 = x^4+ 4x^3 + 6x^2 + 4x + 1

4x^3 = (x+1)^4 - x^4 - 6x^2 - 4x - 1

x^3 = (1/4){(x+1)^4 - x^4} - (3/2)x^2 - x - (1/4)

Now put x =1,2,3...., n and add

you will get

{n(n+1)/2}^2 Ans

While adding all terms have to be added separately