Question

sum to n terms the series, whose nth term is 2^n+3n-1.​

Answer 1

Answer:

2 ( 2^n - 1 ) + 3n(n-1)/2

Step-by-step explanation:

S = ∑ ( 2^n+3n-1 ​) = ∑2^n+ ∑3n -  ∑1

S = 2 ( 2^n - 1 ) + 3n(n+1)/2 - n = 2 ( 2^n - 1 ) + 3n(n-1)/2