sum two numbers is 80. the greater number exceeds the smaller number by twice the smaller number. find the number
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Answered by
2
Answer:
the no is 26.6
Step-by-step explanation:
x+2x = 3x
(x is for the smaller number and since the bigger number is twice of x then, it will be 2x)
3x=80
x=26.6
2x= 57.2
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Answered by
0
Let the number be x
Then greater number = 2x + 11
Sum of two numbers = 80
x + 2 + 11 = 80
3x = 80 - 11
3x = 69
x = 23
Hence, smaller number = 23
Greater number = 2 × 23 + 11 = 57
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