Question

sum up the following series 1^3/1+1^3+2^3/2+1^3+2^3+3^3/3..........to n terms​

Answer 1

Answer:

As written (with 3n as the final term), the sum is infinity.

A more typical problem about the sum of a decreasing (converging) geometric series would be this:

1+131+132+133+⋯+13n

The formula for the sum of a converging geometric series is:

Sn=a1(1−rn)1−r, where a1is the first term and r is the common ratio.

Use this formula with a1=1 and r=13 :

Sn=1(1−(13)n)1−13=123=32