Question

Sum
x+3y and 3x-y subtract sy​

Answer 1

Answer:

Sum of x+3y and -3x-y

= (x+3y) + (-3x-y)

= (x-3x) + (3y-y)

= -2x+2y

Now according to question

subtract (x-y ) from it

Thus,

= (-2x+2y)- (x-y)

= (-2x-x) + ( 2y+y)

= -3x+3y

= -3(x-y)

Hope this helps you

Answer 2

Answer:

Sum of x+3y and -3x-y

= (x+3y) + (-3x-y)

= (x-3x) + (3y-y)

= -2x+2y

Now according to question

subtract (x-y ) from it

Thus,

= (-2x+2y)- (x-y)

= (-2x-x) + ( 2y+y)

= -3x+3y

= -3(x-y)

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