Question

Suma is 3 times as old as her son is now. If 8 years ago she was 5 times his age, find their present age​

Answer 1

Answer:

Step-by-step explanation:

Let present age of suma be x and her son be y

Given,

x=3(y) and

Before 8 years suma age is x-8 and her son age is y-8

x-8 = 5(y-8)

put eq 1 in eq2

3y-8=5y-40

40-8=5y-3y

32=2y

y=16

Put y=16 in eq x=3y we get

x=3(16)

x=48

So suma's age is 48 and her son is 16 years old at present

Answer 2

Answer:

let the age of son =x

age of suma=3x

8 years ago:

son = x-8

suma = 3x-8

3x-8=5(x-8)

3x-8=5x-40

5x-3x=40-8

2x=32

x=16