Math, asked by thopteyugandhara, 1 day ago

Suman and Harpreet had some money in the ratio 5:2. Suman had Rs.300. If Harpreet's money consists of only 5 Rs. coins, how many coins did Harpreet have?​

Answers

Answered by 11576
0

Rs=60

Step-by-step explanation:

Suman: Harpeet

5:2

Suman has money=5k\

harpeet= 2k

5k= rupees 300

k= 300/5

k= RS 60

Harpeet has money= 60

Answered by dayanidhisharma19
0

Answer:

So, Harpreet has 24 Rs 5 coins.

Step-by-step explanation:

Let the money owned by Suman be 5x

So, 5x=300

So, x=60

So the money owned by Harpreet is 2x

=2×60

=120

Now, since Harpreet has only Rs 5 coins,

Number of coins Harpreet has=120/5

=24

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